$\boldsymbol{\mathbf{{\color{Blue}\left(1+\frac{1}{5x}\right)^{{\color{Red}^{5x+1}}}=\left(1+\frac{1}{9}\right)^{{\color{Red}^{9}}}}}}$ $\boldsymbol{\mathbf{{\color{Blue}\left(208+120\sqrt{3}\right)^{{\color{Red}^{\frac{1}{6}}}}={\color{red}?}}}}$ $\boldsymbol{\mathbf{{\color{Blue}\left(\frac{1}{5}\right)^{\frac{1}{5}}}}=?}}}$ $\boldsymbol{\mathbf{{\color{Blue}5^{{\color{Blue}^{11}}}-3^{{\color{Blue}^{2}}}=?}}}$ ${\color{Red}}\boldsymbol{\mathbf{{\color{Blue}9^{{\color{blue}}^{{\color{Blue}4}}}}}}^{\mathbf{{\color{Blue}^{{\color{Red}m}}}}}\mathbf{{\color{Blue}=}^{{\color{white}4}}{\color{Blue}4^{{\color{Blue}^{9}}}}}\mathbf{{\color{Red}^{{\color{Red}^{{\color{Red}^{m}}}}}}}$ $https://latex.codecogs.com$ $\boldsymbol{\mathbf{{\color{Blue}243^{{\color{Blue}^{x^{2}}}}}{\color{Blue}=x^{{\color{red}45}}}}$ $\boldsymbol{\mathbf{{\color{Red}\sqrt{{\color{Blue}1111222225}}{\color{Red}=?}}}}$ ${\color{Red}}\boldsymbol{\mathbf{{\color{Blue}a^{{\color{Red}a}}b^{{\color{Red}b}}=8a^{\color{Red}b}b^{{\color{Red}a}}}$ $\boldsymbol{\mathbf{{\color{Blue}a^{{\color{Blue}^{4}}}+b^{{\color{Blue}^{4}}}=10a^{{\color{Blue}^{2}}}b^{{\color{Blue}^{2}}}}}}$ ${\boldsymbol{\mathbf{{\color{Blue}\left(x-5\right){\color{Red}!}=3{\color{Red}!}\times 5{\color{Red}!}\times 7{\color{Red}!}}}}}$ $\boldsymbol{\mathbf{{\color{Blue}m+2mn+n=38}}}$ $\boldsymbol{\mathbf{{\color{Red}\sqrt{{\color{Blue}1111222225}}{\color{Red}={\color{Blue}?}}}}}$ $\boldsymbol{\mathbf{{\color{Blue}x^{{\color{Red}2}}+\left(\frac{3x}{x-3}\right)^{{\color{Red}2}}=16}}}$ $\begin{alignat}\mathbf{{\color{Black}5^{{\color{Black}^{m}}}-3^{{\color{Black}^{m}}}=544}}\\\mathbf{m=?}\end{alignat}$ $\boldsymbol{\mathbf{{\color{Blue}64^{{\color{Blue}^{x}}}={\color{Blue}x^{{\color{Blue}192}}}}}}$ $\boldsymbol{\mathbf{{\color{Blue}\frac{2^{{\color{Red}11}}+4^{{\color{Red}11}}+8^{{\color{Red}11}}}{8^{{\color{Red}11}}-1}}{\color{Blue}=?}}}$ $\boldsymbol{\mathbf{{\color{Blue}\frac{43^{{\color{red}^{3}}}+23^{{\color{red}^{3}}}}{20^{{\color{Blue}^{3}}}+43^{{\color{Blue}^{3}}}}=?}}}$ $\boldsymbol{\mathbf{{\color{Blue}9^{{\color{red}^{x}}}-{\color{Blue}x^{{\color{Blue}4}}}=65}}}$ $\begin{alignat}{\color{Blue}\mathbf{\sqrt{{\color{black}9+4}\sqrt{{\color{black}4+2}\sqrt{{\color{black}6}}}}}}\end{alignat}\\$ $\begin{alignat}{\color{Red}\sqrt[\mathbf{3}]{{\color{black}\mathbf{x+28}}}}-{\color{Red}\sqrt[\mathbf{3}]{{\color{black}\mathbf{x-28}}}}\end{alignat}=\mathbf{2}$ $\boldsymbol{\mathbf{{\color{Blue}\left(\frac{x}{10}\right)^{{\color{Red}2}}}{{\color{Blue}+}\color{Blue}\left(\frac{x}{2x-10}\right)^{{\color{Red}2}}=2}}}$ $\mathbf{\sqrt{\frac{11^{{\color{Red}^{4}}}+100^{{\color{Red}^{4}}}+111^{{\color{Red}^{4}}}}{2}}}$ $\boldsymbol{\mathbf{{\color{Blue}x^{{\color{Red}x^{2}-1}}=3^{{\color{Red}2x^{2}-2}}}}}$ $\mathbf{\left(x-\frac{1}{x}\right)^{{\color{Red}^{1/_2}}}+\left(1-\frac{1}{x}\right)^{{\color{Red}^{1/_2}}}=x}$ $\boldsymbol{\mathbf{{\color{Blue}\sqrt{\frac{{\color{Blue}\sqrt{12}}}{9+\sqrt{108}}}=?}}}$ $\mathbf{\left(x+2\right){\color{Red}!}+x^{{\color{Red}{3}}}=x^{{\color{Red}5}}}$

First Name	Gender	Age
Joshua	Male	36
Michelle	Female	10

There is a parents meeting in next month that everybody is encouraged to buy graduation gowns for their kids

$\mathbf{4^{{\color{Red}^{{\color{Red}\frac{1}{\sqrt{x}}}}}}+16^{{\color{Red}^{{\color{Red}\frac{1}{\sqrt{x}}}}}}=64^{{\color{Red}^{\frac{1}{\sqrt{x}}}}}}$ $\begin{alignat}\mathbf{{\color{black}\sqrt{\frac{x+y}{2}}+\sqrt{\frac{x-y}{3}}=2\sqrt{7}}}\\\mathbf{\sqrt{\frac{x+y}{8}}-\sqrt{\frac{x-y}{12}}=\sqrt{3}}\end{alignat}$ $\begin{cases}\boldsymbol{\mathbf{{\color{Blue}x+xy-y=7}}}\\\boldsymbol{\mathbf{{\color{Blue}x^{2}y}{\color{Blue}-xy^{2}=6}}}\end{cases}$ $\mathbf{x^{{\color{Red}x^{2}}}=x^{{\color{Red}3x+1}}}$ $\mathbf{\frac{1}{x^{{\color{Red}^{2}}}}-\frac{1}{\left(x+1\right)^{{\color{Red}^{2}}}}=1}$

My first PHP Scripting

$\boldsymbol{\mathbf{{\color{Blue}\frac{25^{{\color{Red}^{20}}}-25^{{\color{Red}^{18}}}}{25^{{\color{Red}^{10}}}+25^{{\color{Red}^{9}}}}}{\color{Blue}=?}}}$ $\begin{alignat}\mathbf{{\color{black}x=\sqrt{3+\sqrt{8}}}}\\\mathbf{x^{{\color{Red}^{6}}}-{\color{Red}m}x^{{\color{Red}^{3}}}=-1}\end{alignat}$ $\begin{alignat}\mathbf{{\color{black}x=\sqrt{3+\sqrt{8}}}}\\\mathbf{x^{{\color{Red}6}}-{\color{Red}m}x^{{\color{Red}3}}}\end{alignat}$ $\mathbf{\sqrt[3]{63+\sqrt{x}}+\sqrt[3]{63-\sqrt{x}}=6}$ $\begin{alignat}\mathbf{{\color{Black}3x-x^{{\color{Red}^{2}}}=23}}\\\mathbf{{\color{Black}\left(x-1\right)^{{\color{Red}^{4}}}+{\color{Black}\left(x-2\right)^{{\color{Red}^{4}}}}=?}}\end{alignat}$ $\mathbf{sin^{{\color{Red}6}}x+cos^{{\color{Red}6}}x=\frac{1}{4}}$ $\mathbf{9^{{\color{Red}^{\frac{1}{\sqrt{x}}}}}-6^{{\color{Red}^{\frac{1}{\sqrt{x}}}}}=4^{{\color{Red}^{\frac{1}{\sqrt{x}}}}}}$ $\mathbf{\sqrt[{\color{Red}\mathbf{5}}]{\mathbf{16+\sqrt{x}}}+\mathbf{\sqrt[\mathbf{{\color{Red}5}}]{\mathbf{16-\sqrt{\mathbf{x}}}}=\mathbf{2}}$ $\mathbf{x^{{\color{Red}^{6}}}+\left(x+3\right)^{{\color{Red}^{6}}}=65}$ $\mathbf{\sqrt{36+4\sqrt{35}+2\sqrt{15}}}$ $\mathbf{x^{{\color{Red}6}}+\left(x+3\right)^{{\color{Red}6}}=65}$ $\mathbf{\sqrt{36+4\sqrt{35}+2\sqrt{15}+4\sqrt{21}}}$ $\mathbf{\left(x-4\right)^{{\color{Red}4}}=x^{{\color{Red}4}}}$ $\mathbf{{\color{Blue}\mathbf{\sqrt[x]{9\sqrt{3\sqrt{3}}}}=27}}$ $\mathbf{\left(\sqrt{\sqrt{25}-\sqrt{24}}\right)^{{\color{Red}x}}={\color{Red}x}}$ $\mathbf{\left\{5-24^{{\color{Red}^{\frac{1}{2}}}}\right\}^{{\color{Red}^{\frac{x}{2}}}}={\color{Red}x}}$ ${\color{Red}}\mathbf{\left(5-24^{{\color{Red}^{\frac{1}{2}}}}\right)^{{\color{Red}^{\frac{x}{2}}}}={\color{Red}x}}$ $\mathbf{\left(5-24^{{\color{Red}^{{\color{Red}\frac{1}{2}}}}}\right)^{{\color{Red}\frac{x}{2}}}={\color{Red}x}}$ $\mathbf{\left(5-\sqrt{24}\right)^{{\color{Red}^{\mathbf{x}}}}={\color{Red}x^{2}}}$ $\mathbf{x^{{\color{Red}^{2/_x}}}=5-\sqrt{24}}$ $\mathbf{{\color{Red}x^{{\color{black}2}}}=\left(5-\sqrt{24}\right)^{{\color{Red}^{x}}}}$ $\mathbf{x-\sqrt{x^{{\color{Red}^{2}}}-\sqrt{x^{{\color{Red}^{3}}}-2}}=1}$ $\mathbf{\sqrt{2-\sqrt{3}}+\frac{2}{\sqrt{3}+1+\sqrt{2}}}$ $\mathbf{\frac{x^{{\color{Red}2}}}{3}+\frac{48}{x^{{\color{Red}2}}}=10\left(\frac{x}{3}-\frac{4}{x}\right)}$ $\mathbf{\frac{x^{{\color{Red}2}}}{3}+\frac{48}{x^{{\color{Red}^{2}}}}=10\left(\frac{x}{3}-\frac{4}{x}\right)}$ $\mathbf{\sqrt[\mathbf{3}]{\mathbf{8}+\mathbf{3\sqrt{\mathbf{21}}}}+\mathbf{\sqrt[\mathbf{3}]{\mathbf{8}-\mathbf{3\sqrt{\mathbf{21}}}}}}$ $\mathbf{\frac{\mathbf{9}}{\mathbf{x^{{\color{Red}2}}}}+\frac{\mathbf{2x}}{\sqrt{\mathbf{2x^{{\color{Red}2}}+9}}}=1}$ $\mathbf{\left(\frac{-1+i\sqrt{3}}{2}\right)^{{\color{Red}6}}+\mathbf{\left(\frac{-1-i\sqrt{3}}{2}\right)^{{\color{Red}6}}}}$ $\mathbf{{\color{Green}x=\sqrt{2+\sqrt{2-\sqrt{2+x}}}}}$ $\mathbf{x=\sqrt{2+\sqrt{2-\sqrt{2+x}}}}$

The background-color Property

$\mathbf{{\color{Green}x=\sqrt{2+\sqrt{2-\sqrt{2+x}}}}}$

The background color can be specified with a color name.

Math Solver

Enter Equation:

$\mathbf{{\color{Green}\sqrt{x}^{{\color{Green}^{log\left(\sqrt{10}\right)}}}=10^{{\color{Green}^{\sqrt{10}}}}}}$ $\mathbf{{\color{Green}\left(x+2\right)^{{\color{Green}^{4}}}+\left(x+1\right)^{{\color{Green}^{4}}}=17}}$ $\boldsymbol{{\color{white}27^{{\color{white}^{x}}}=\sqrt[3]{3^{{\color{white}^{\sqrt{x}}}}}}}$ $\boldsymbol{{\color{Blue}27^{{\color{Blue}^{x}}}=\sqrt[3]{3^{{\color{Blue}^{\sqrt{x}}}}}}}$