\inline&space;\huge&space;\dpi{400}\bg{white}\begin{alignat}\mathbf{{\color{Black}m+n=72}}\\\\\mathbf{{\color{Black}8^{{\color{Red}^{m}}}}{\color{Black}-4^{\color{Red}^{m}}=18}}\\\mathbf{{\color{Red}m=?}}\end{alignat} $\inline&space;\huge&space;\dpi{600}\bg{yellow}\mathbf{\left(\frac{1}{y}\right)^{{\color{Red}m}}+\left(\frac{1}{y}\right)^{{\color{Red}1/_2}}=1}$ \inline&space;\huge&space;\dpi{400}\bg{White}\begin{alignat}\mathbf{{\color{Black}3^{{\color{Black}^{x}}}+3^{{\color{Black}^{y}}}=19764}}\\\mathbf{x+y=13}\\ \mathbf{{\color{Red}x,y=?}} \end{alignat} $\inline&space;\huge&space;\dpi{400}\mathbf{{\color{black}5^{{\color{Red}^{x}}}}=5{\color{Red}x}+15}$ \inline&space;\huge&space;\dpi{400}\begin{alignat}\mathbf{{\color{black}p^{{\color{Red}^{1/_3}}}}{\color{black}+q^{{\color{Red}^{1/_3}}}}{\color{black}+r^{{\color{Red}^{1/_3}}}}{\color{black}=0}}\\\mathbf{{\color{Black}\left(p+q+r\right)^{{\color{Red}^{3}}}=?}}\end{alignat} \inline&space;\huge&space;\dpi{400}\begin{alignat}\mathbf{{\color{black}p+p^{{\color{Red}^{-1}}}=3}}\\\mathbf{{\color{black}p^{{\color{Red}^{1/_4}}}}{\color{black}+}{\color{black}p^{{\color{red}^{-1/_4}}}=?}}\end{alignat} \inline&space;\huge&space;\dpi{300}{\begin{alignat}\mathbf{{\color{Black}x^{{\color{Red}^{1/_2}}}+y^{{\color{Red}^{1/_4}}}=\frac{1}{2}}}\\\mathbf{{\color{Black}x^{{\color{Red}^{1/_4}}}+y^{{\color{Red}^{1/_2}}}=\frac{1}{2}}}\end{alignat}} \inline&space;\huge&space;\dpi{400}\begin{alignat}{\color{Blue}\mathbf{\sqrt{{\color{black}9+4}\sqrt{{\color{black}4+2}\sqrt{{\color{black}3}}}}}}\end{alignat}\\ \inline&space;\huge&space;\dpi{400}\begin{alignat}{\color{Red}\sqrt[\mathbf{3}]{{\color{black}\mathbf{x+28}}}}-{\color{Red}\sqrt[\mathbf{3}]{{\color{black}\mathbf{x-28}}}}\end{alignat}=\mathbf{2} $\inline&space;\huge&space;\dpi{400}\mathbf{\sqrt{\frac{11^{{\color{Red}^{4}}}+100^{{\color{Red}^{4}}}+111^{{\color{Red}^{4}}}}{2}}}$ $\inline&space;\huge&space;\dpi{400}\mathbf{{\color{black}49^{{\color{Red}^{{\color{Red}x}}}}={\color{Red}x{\color{black}^{14}}}}}$ $\inline&space;\huge&space;\dpi{800}\mathbf{\left(x-\frac{1}{x}\right)^{{\color{Red}^{1/_2}}}+\left(1-\frac{1}{x}\right)^{{\color{Red}^{1/_2}}}=x}$ \inline&space;\huge&space;\dpi{300}\begin{alignat}\mathbf{{\color{Blue}a=\sqrt{5-2\sqrt{6}}}}\\\mathbf{{\color{Pink}b=\sqrt{3-2\sqrt{2}}}}\\\mathbf{{\color{Red}c=\sqrt{7-2\sqrt{12}}}}\\\end{alignat} $\inline&space;\huge&space;\dpi{300}\mathbf{\left(x+2\right){\color{Red}!}+x^{{\color{Red}{3}}}=x^{{\color{Red}5}}}$
First Name Gender Age
Joshua Male 36
Michelle Female 10

There is a parents meeting in next month that everybody is encouraged to buy graduation gowns for their kids

$\inline&space;\huge&space;\dpi{400}\mathbf{4^{{\color{Red}^{{\color{Red}\frac{1}{\sqrt{x}}}}}}+16^{{\color{Red}^{{\color{Red}\frac{1}{\sqrt{x}}}}}}=64^{{\color{Red}^{\frac{1}{\sqrt{x}}}}}}$ \inline&space;\huge&space;\dpi{400}\begin{alignat}\mathbf{{\color{black}\sqrt{\frac{x+y}{2}}+\sqrt{\frac{x-y}{3}}=\sqrt{28}}}\\\mathbf{\sqrt{\frac{x+y}{8}}-\sqrt{\frac{x-y}{12}}=\sqrt{3}}\end{alignat} $\inline&space;\huge&space;\dpi{400}\mathbf{x^{{\color{Red}^{{\color{Red}x^{2}}}}}=x^{{\color{Red}^{3x+1}}}}$ $\inline&space;\huge&space;\dpi{400}\mathbf{x^{{\color{Red}x^{2}}}=x^{{\color{Red}3x+1}}}$ $\inline&space;\huge&space;\dpi{400}\mathbf{\frac{1}{x^{{\color{Red}^{2}}}}-\frac{1}{\left(x+1\right)^{{\color{Red}^{2}}}}=1}$

# My first PHP Scripting

$\inline&space;\huge&space;\dpi{800}\mathbf{9^{{\color{Red}^{\frac{1}{\sqrt[3]{x}}}}}=90}$ \inline&space;\huge&space;\dpi{400}\begin{alignat}\mathbf{{\color{black}x=\sqrt{3+\sqrt{8}}}}\\\mathbf{x^{{\color{Red}^{6}}}-{\color{Red}m}x^{{\color{Red}^{3}}}+1=0}\end{alignat} \inline&space;\huge&space;\dpi{400}\begin{alignat}\mathbf{{\color{black}x=\sqrt{3+\sqrt{8}}}}\\\mathbf{x^{{\color{Red}6}}-{\color{black}m}x^{{\color{Red}3}}+1=0}\end{alignat} $\inline&space;\huge&space;\dpi{400}\mathbf{\sqrt[3]{63+\sqrt{x}}+\sqrt[3]{63-\sqrt{x}}=6}$ \inline&space;\huge&space;\dpi{400}\begin{alignat}\mathbf{{\color{Black}3x-x^{{\color{Red}^{2}}}=23}}\\\mathbf{{\color{Black}\left(x-1\right)^{{\color{Red}^{4}}}+{\color{Black}\left(x-2\right)^{{\color{Red}^{4}}}}=?}}\end{alignat} $\inline&space;\huge&space;\dpi{400}\mathbf{sin^{{\color{Red}6}}x+cos^{{\color{Red}6}}x=\frac{1}{4}}$ $\inline&space;\huge&space;\dpi{800}\mathbf{9^{{\color{Red}^{\frac{1}{\sqrt{x}}}}}-6^{{\color{Red}^{\frac{1}{\sqrt{x}}}}}=4^{{\color{Red}^{\frac{1}{\sqrt{x}}}}}}$ $\inline&space;\huge&space;\dpi{400}\mathbf{\sqrt[{\color{Red}\mathbf{5}}]{\mathbf{16+\sqrt{x}}}+\mathbf{\sqrt[\mathbf{{\color{Red}5}}]{\mathbf{16-\sqrt{\mathbf{x}}}}=\mathbf{2}}$ $\inline&space;\huge&space;\dpi{300}\mathbf{x^{{\color{Red}^{6}}}+\left(x+3\right)^{{\color{Red}^{6}}}=65}$ $\inline&space;\huge&space;\dpi{300}\mathbf{\sqrt{36+4\sqrt{35}+2\sqrt{15}}}$ $\inline&space;\huge&space;\dpi{400}\mathbf{x^{{\color{Red}6}}+\left(x+3\right)^{{\color{Red}6}}=65}$ $\inline&space;\huge&space;\dpi{300}\mathbf{\sqrt{36+4\sqrt{35}+2\sqrt{15}+4\sqrt{21}}}$ $\inline&space;\huge&space;\dpi{400}\mathbf{\left(x-4\right)^{{\color{black}4}}=x^{{\color{black}4}}}$ $\inline&space;\huge&space;\dpi{450}\mathbf{\left(\sqrt{\sqrt{25}-\sqrt{24}}\right)^{{\color{Red}x}}={\color{Red}x}}$ $\inline&space;\huge&space;\dpi{150}\mathbf{\left\{5-24^{{\color{Red}^{\frac{1}{2}}}}\right\}^{{\color{Red}^{\frac{x}{2}}}}={\color{Red}x}}$ $\inline&space;\huge&space;\dpi{450}{\color{Red}}\mathbf{\left(5-24^{{\color{Red}^{\frac{1}{2}}}}\right)^{{\color{Red}^{\frac{x}{2}}}}={\color{Red}x}}$ $\inline&space;\huge&space;\dpi{450}\mathbf{\left(5-24^{{\color{Red}^{{\color{Red}\frac{1}{2}}}}}\right)^{{\color{Red}\frac{x}{2}}}={\color{Red}x}}$ $\inline&space;\huge&space;\dpi{350}\mathbf{\left(5-\sqrt{24}\right)^{{\color{Red}^{\mathbf{x}}}}={\color{Red}x^{2}}}$ $\inline&space;\huge&space;\dpi{350}\mathbf{x^{{\color{Red}^{2/_x}}}=5-\sqrt{24}}$ $\inline&space;\huge&space;\dpi{350}\mathbf{{\color{Red}x^{{\color{black}2}}}=\left(5-\sqrt{24}\right)^{{\color{Red}^{x}}}}$ $\inline&space;\huge&space;\dpi{450}\mathbf{x-\sqrt{x^{{\color{Red}^{2}}}-\sqrt{x^{{\color{Red}^{3}}}-2}}=1}$ $\inline&space;\huge&space;\dpi{400}\mathbf{\sqrt{2-\sqrt{3}}+\frac{2}{\sqrt{3}+1+\sqrt{2}}}$ $\inline&space;\huge&space;\dpi{400}\mathbf{\frac{x^{{\color{Red}2}}}{3}+\frac{48}{x^{{\color{Red}2}}}=10\left(\frac{x}{3}-\frac{4}{x}\right)}$ $\inline&space;\huge&space;\dpi{400}\mathbf{\frac{x^{{\color{Red}2}}}{3}+\frac{48}{x^{{\color{Red}^{2}}}}=10\left(\frac{x}{3}-\frac{4}{x}\right)}$ $\inline&space;\huge&space;\dpi{450}\mathbf{\sqrt[\mathbf{3}]{\mathbf{8}+\mathbf{3\sqrt{\mathbf{21}}}}+\mathbf{\sqrt[\mathbf{3}]{\mathbf{8}-\mathbf{3\sqrt{\mathbf{21}}}}}}$ $\inline&space;\huge&space;\dpi{400}\mathbf{\frac{\mathbf{9}}{\mathbf{x^{{\color{Red}2}}}}+\frac{\mathbf{2x}}{\sqrt{\mathbf{2x^{{\color{Red}2}}+9}}}=1}$ $\inline&space;\huge&space;\dpi{400}\mathbf{\left(\frac{-1+i\sqrt{3}}{2}\right)^{{\color{Red}6}}+\mathbf{\left(\frac{-1-i\sqrt{3}}{2}\right)^{{\color{Red}6}}}}$ $\inline&space;\huge&space;\dpi{400}\bg{black}\mathbf{{\color{Green}x=\sqrt{2+\sqrt{2-\sqrt{2+x}}}}}$ $\inline&space;\huge&space;\dpi{400}\mathbf{x=\sqrt{2+\sqrt{2-\sqrt{2+x}}}}$

# The background-color Property

$\inline&space;\huge&space;\dpi{420}\bg{black}\mathbf{{\color{Green}x=\sqrt{2+\sqrt{2-\sqrt{2+x}}}}}$

The background color can be specified with a color name.

Math Solver
$\inline&space;\huge&space;\dpi{400}\bg{black}\mathbf{{\color{Green}\sqrt{x}^{{\color{Green}^{log\left(\sqrt{x}\right)}}}=10^{{\color{Green}^{\sqrt{10}}}}}}$ $\inline&space;\huge&space;\dpi{400}\bg{black}\mathbf{{\color{Green}\left(x+2\right)^{{\color{Green}^{4}}}+\left(x+1\right)^{{\color{Green}^{4}}}=17}}$